प्रतिलोम त्रिकोणमितीय फलन| Class 12 Math Chapter 2 One Shot |Inverse Trigonometric Function Revision
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प्रतिलोम त्रिकोणमितीय फलन| Class 12 Math Chapter 2 One Shot |Inverse Trigonometric Function Revision
3.3K views1 month ago
YouTubeAlpha Institute
Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths
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Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths
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YouTubeShivang Maths Academy
Q) The value of 𝑘 for which the function 𝑓(𝑥)={(𝑥^2 sin 1/𝑥, 𝑥≠0 𝑘(𝑥+1), 𝑥=0) is a continuo
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Q) The value of 𝑘 for which the function 𝑓(𝑥)={(𝑥^2 sin 1/𝑥, 𝑥≠0 𝑘(𝑥+1), 𝑥=0) is a continuo
3.9K views2 weeks ago
YouTubeShivang Maths Academy
Q) If 𝑓(𝑥)={(sin𝑥/𝑥+cos𝑥, 𝑥≠0 𝑘, 𝑥=0) is continuous at 𝑥=0, then the value of 𝑘 is :
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Q) If 𝑓(𝑥)={(sin𝑥/𝑥+cos𝑥, 𝑥≠0 𝑘, 𝑥=0) is continuous at 𝑥=0, then the value of 𝑘 is :
2.4K views1 week ago
YouTubeShivang Maths Academy
Q) Domain of 𝑓(𝑥)=cos^(−1) 𝑥+sin𝑥 is(A) 𝑅(B) (−1,1)(C) [−1,1](D) 𝜙
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Q) Domain of 𝑓(𝑥)=cos^(−1) 𝑥+sin𝑥 is(A) 𝑅(B) (−1,1)(C) [−1,1](D) 𝜙
707 views6 days ago
YouTubeShivang Maths Academy
Draw the graph of 𝑓(𝑥)=𝑠𝑖𝑛^(−1) 𝑥, 𝑥∈[−1/√2, 1/√2]. Also, write range of f(x). #trigonometry
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Draw the graph of 𝑓(𝑥)=𝑠𝑖𝑛^(−1) 𝑥, 𝑥∈[−1/√2, 1/√2]. Also, write range of f(x). #trigonometry
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YouTubeShivang Maths Academy
Q) Simplify : tan^(−1) {√((1−cos𝑥)/(1+cos𝑥))}}#class12maths #shivangmathsacademy #cbsemaths
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Q) Simplify : tan^(−1) {√((1−cos𝑥)/(1+cos𝑥))}}#class12maths #shivangmathsacademy #cbsemaths
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YouTubeShivang Maths Academy
2:11
Q) Check whether function f(x) defined as f(𝑥)={((|𝑥−3|)/(2(𝑥−3)), 𝑥=3 (𝑥−6)/6,𝑥≥3) Is
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YouTubeShivang Maths Academy
2:33
Q) Simplest form of tan^(−1) ((√(1+cosx)+√(1−cosx))/(√(1+cosx)−√(1−cosx))), π=x=3π/2 is#class
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YouTubeShivang Maths Academy
1:08
Q) Simplify : sin(2sin^(−1) 0.6)#class12maths #shivangmathsacademy #cbsemaths #class12
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YouTubeShivang Maths Academy
2:13
Q) If 𝑓(𝑥)={ ((𝑥^2−4𝑥−5)/(𝑥+1), 𝑥≠−1 𝑘,&𝑥=−1 is continuous at 𝑥=−1, then the value of 𝑘 i
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YouTubeShivang Maths Academy
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Q) Find the domain of 𝑝(𝑥)=sin^(−1) (1−2𝑥^2 ). Hence,find the value of 𝑥 for which p(𝑥)=𝜋/6.
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YouTubeShivang Maths Academy
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Q) If 2cos^(−1) 𝑥 = 𝑦,then(A) 0≤𝑦≤𝜋(B) −𝜋≤𝑦≤𝜋(C) 0≤𝑦≤2𝜋(D) −𝜋≤𝐲 ≤ 0 #shivangmathsacademy
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